4.9x^2-29x+4=0

Solution for 4.9x^2-29x+4=0 equation:

4.9x^2-29x+4=0

a = 4.9; b = -29; c = +4;
Δ = b2-4ac
Δ = -292-4·4.9·4
Δ = 762.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{762.6}}{2*4.9}=\frac{29-\sqrt{762.6}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{762.6}}{2*4.9}=\frac{29+\sqrt{762.6}}{9.8}
$